Author Topic: Clarification about Wheel of Fortune taxation method  (Read 1185 times)

carca82

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Clarification about Wheel of Fortune taxation method
« on: September 19, 2022, 03:11:38 PM »
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Every player receives points for his knights. For each knight, the player earns 1 point for each pennant in the city, plus 1 point for each of their knights in the city.

A question: are separate cities counted separately or together? Look at the following scenario:



If counted separately, the two pink cities are worth 2 points each, for a total of 4. If counted together, they are worth a grandtotal of 8 points. What's the correct one?


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Offline kothmann

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Re: Clarification about Wheel of Fortune taxation method
« Reply #1 on: September 19, 2022, 03:43:24 PM »
I would score 4 for pink.

Offline corinthiens13

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Re: Clarification about Wheel of Fortune taxation method
« Reply #2 on: September 19, 2022, 11:06:58 PM »
Cities are counted separately, for each knight, 1 point per pennant and per knight in his city. 4 points in your scenario  :yellow-meeple:

carca82

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Re: Clarification about Wheel of Fortune taxation method
« Reply #3 on: September 20, 2022, 03:08:28 AM »
Thank you for the confirmation. I know I'm being extremely pedantic here but I'd like to propose a small change in how the rule is written out. From
Quote
Every player receives points for his knights. For each knight, the player earns 1 point for each pennant in the city, plus 1 point for each of their knights in the city.

to
Quote
Every player receives points for his knights. For each city, for each knight the player earns 1 point for each pennant in the city, plus 1 point for each of their knights in the city.

I know the sentence says "city" (singular) twice and maybe it was already clear enough but now it would be even clearer :pink-meeple:

Offline Bumsakalaka

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Re: Clarification about Wheel of Fortune taxation method
« Reply #4 on: September 20, 2022, 04:16:12 AM »
Ts is not necessary. Because you are going from the beginning of sentence. For each knight. So if I read it correctly then if you have for example two knights in city with one shield, then you score
1st knight - 1point for shield and 2 points for knights in city
2!s knight - same

So in the final you score 6 points, didn't you?

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carca82

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Re: Clarification about Wheel of Fortune taxation method
« Reply #5 on: September 20, 2022, 05:45:23 AM »
you are going from the beginning of sentence. For each knight.
This doesn't necessarely say that I have to consider cities separately. "For each knight" says that I have to consider every knight and apply an algoritm to them. Nowhere it's said that I have to consider every city separately, I think.
But it's ok, not a big problem.

Offline corinthiens13

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Re: Clarification about Wheel of Fortune taxation method
« Reply #6 on: September 20, 2022, 06:13:46 AM »
It's written "in the city", if we had to count every city, it would be written "in a city" or "in the cities". I know it's something a headache to analyze the rules when so little words may imply a big difference  :yellow-meeple:

Offline DIN0

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Re: Clarification about Wheel of Fortune taxation method
« Reply #7 on: September 21, 2022, 07:36:41 AM »
This is really easy. For each separate city you make the following calculation: v=k*(k+p)
k - number of knights
p - number of pennants
v - victory points gained

only knights belonging to the player are considered.

Offline Meepledrone

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Re: Clarification about Wheel of Fortune taxation method
« Reply #8 on: September 21, 2022, 08:26:00 AM »
Yes, it is an odd scoring... I think of it as a distant cousin of the Gingerbread Man bonus...
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Offline kothmann

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Re: Clarification about Wheel of Fortune taxation method
« Reply #9 on: September 21, 2022, 09:57:07 AM »
For each separate city you make the following calculation: v=k*(k+p)
I love this, but most of my friends prefer "rules with no algebra".   ;)

I prefer the current concise wording, but it would be nice to add another meeple (red or blue) in the lower left corner of this example image:

The extra meeple earns 1 point, making things a bit clearer.

Offline DIN0

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Re: Clarification about Wheel of Fortune taxation method
« Reply #10 on: September 21, 2022, 11:08:23 AM »
Quote
   
Quote
For each separate city you make the following calculation: v=k*(k+p)

I love this, but most of my friends prefer "rules with no algebra".   ;)
Understandable. I came up with this formula long ago to help me better visualize and remember the scoring process  ^-^ (it's also shorter to write).
Perhaps it will aid @Sir Lose-a-Farm in his gaming experience.
« Last Edit: September 21, 2022, 11:11:09 AM by DIN0 »

carca82

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Re: Clarification about Wheel of Fortune taxation method
« Reply #11 on: September 21, 2022, 01:09:08 PM »
This is really easy. For each separate city you make the following calculation: v=k*(k+p)
Never said it wasn't easy, my question was about the "For each separate city" part

but it would be nice to add another meeple (red or blue) in the lower left corner of this example image:

The extra meeple earns 1 point, making things a bit clearer.
That would be extremely helpful IMO, that would have totally prevented the doubt that started this cursed thread 
« Last Edit: September 21, 2022, 01:12:50 PM by Sir Lose-a-Farm »

Offline Bumsakalaka

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Re: Clarification about Wheel of Fortune taxation method
« Reply #12 on: September 21, 2022, 01:45:41 PM »
For each separate city you make the following calculation: v=k*(k+p)
I love this, but most of my friends prefer "rules with no algebra".   ;)

I prefer the current concise wording, but it would be nice to add another meeple (red or blue) in the lower left corner of this example image:

The extra meeple earns 1 point, making things a bit clearer.
Not sure about it. What will be score for this example by original rules and how by your simplification?

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Offline Meepledrone

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Re: Clarification about Wheel of Fortune taxation method
« Reply #13 on: September 21, 2022, 04:40:00 PM »
It is not a simplification, but an additional example with two cities with meeples to show that each city is scored separately.


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