Author Topic: TREES question for my next variant.  (Read 605 times)

Offline Meepledrone

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Re: TREES question for my next variant.
« Reply #30 on: July 14, 2019, 06:03:37 AM »
Good afternoon, Meepledrone!

After reading your before post, I have a doubt... You wrote
"Does 24 / 5040 ring a bell? I think so (See the quadruplas table attached.) Well, it is not rocket science: the probability of drawing any quadrupla is equal to the number of COMBINATIONS  for the quadrupla divided by the total of possible quadruplas."

As far as I know, probability calculations are based on " possible cases divided by the total amount of cases ".
So for 4444 quadrupla, it's 24 combinations and also 24 possible cases... But in another different case of" not coincidence ", for example 1223, your 3221, there are 6 COMBINATIONS at your table, but I think that its probability of extraction is" 72/5040 ", and not" 6/5040 “, Am I right?.
I can see also that the addition of all of quadruplas COMBINATION  data at your table, column, can't do 5040, so I suppose that you really referred to Total [possible] cases of every single  quaterna, etc.  in your table.

Hi there CarcaMaker!

Yes, you are right. I was talking about total combinations (column Total in the previous tables) the intermediate columns are just to keep track of how the final figure is obtained, but for your objectives are irrelevant.

Please find below a new version of the same Excel and PNG files where I hid everything not useful for you. I also renamed the offending column to avoid ambiguities.

I discovered finally a mistake in my "Weights" column, next to your table :
I should be written "x4" at 433 triplet weight. I don't know now if there are more mistakes.

I obtained my "weights" values as the inverse of the (my right calculation?) probability, "possible cases divided by total cases", (this is, its inverse), knowing that the "unitary weight" should be the single Pearl extraction case, this is a "x1", and continuing proportionatelly with the other all cases. Is this right?.

(I wanted to meliorate the rarity of the extractions).
Attentively, waiting your response.

I'm glad you solved the issue.

Eager to hear from you.

Cheers!

Offline Carca_Maker

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Re: TREES question for my next variant.
« Reply #31 on: July 14, 2019, 07:32:58 AM »
I thank your help, Meepledrone. I give you +1 merit. Glad to meet you!.

Offline Meepledrone

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Re: TREES question for my next variant.
« Reply #32 on: July 14, 2019, 07:39:16 AM »
Thank you, Carca_Maker!

It's my pleasure! Happy to help.

See you around with your ideas!  :(y)
« Last Edit: July 14, 2019, 07:42:35 AM by Meepledrone »

Offline DrMeeple

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Re: TREES question for my next variant. First results!.
« Reply #33 on: July 15, 2019, 05:09:25 AM »
Hi people! This is a first approximation to my results. It's about trees branches and its weights at my future variant. It's a "dual" file... Sorry. There are pearls 4, emeralds 3, rubíes (in Spanish, red gems, and a diamond!. Thanks Meepledrone, I'm a little busy... I will read your previous post more slowly, I think that I matched with your post, without being read. Luckily!. Cheers!. JEWELS VALIDATIONS AND ITS WEIGHTS.

Like traders and builders mechanism??
'Connected field segments are called farms'  - The Weed Guru

Offline Carca_Maker

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Re: TREES question for my next variant.
« Reply #34 on: July 15, 2019, 07:00:07 AM »
No, DrMeeple but that question about to feed the Constructor it's contemplated, at my Jewels future expansion.


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