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Messages - Meepledrone

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1
Official Rules / Re: Order of play in french
« on: Today at 12:55:02 PM »
Hi there corinthiens13!

"Long" time no talk. Keep up with the great work!

I reviewed the images and would like to comment a few minor issues:
* Page 12 - Festival: There is a festival symbol for C2 (Please check: http://wikicarpedia.com/index.php/The_Festival). The entry displays the C1 version.
* Page 19 - Ville / Cathédrale(s): It displays a C1 cathedral
* Page 19 - Route / + Auberge(s): It displays a C1 inn
* Page 22 - Ville / Cathédrale(s): It displays a C1 cathedral
* Page 23 - Route / + Auberge(s): It displays a C1 inn

Some additional comments on the expansion symbols on page 3 just in case you want to point it out differences between C1 and C2. If you just included them as visual aid, just ignore the following comments:
 
* La rivière: It has only an expansion symbol in the Big Box 5 version
* La rivière II: It may have no symbol for C1
* Hérétiques et autels: It may have no symbol for C1
* Cathares / siège / assiégeants: The symbol shown belongs to Assiégeants (Besiegers). Cathares (Cathars) show a monk symbol and Siège (Siege) has no symbol.
* Le festival: It has different symbols for C1 and C2
* Castles in Germany: iIt has different symbols for C1 and C2

Cheers!

2
General / Re: LEGO Carcassonne Link
« on: July 15, 2019, 04:17:44 PM »
One of the problems with these tiles is you can tell by the border if it's road, city or grass. :)

To solve this issue, you would need a sticker around the tiles, or have blank LEGO tiles and use stickers to add the features, what would beat the original intent IMHO.

LEGO is at full blom in my house and had a chance to put one on display during an event. A rotating jet engine that crashed during move. :( But it all worked out.

Can you share some videos of your collection and MOCs? It would be great! Thanks.

3
Official Rules / Re: The wagon and the Big Top.
« on: July 15, 2019, 07:41:29 AM »
Ok, hard-core C1 stranger!  ;D

Next time you play a mega-Carcassonne game with wagons and players have to remove it after each scoring with C1 rules, please remember my words.

Cheers!

4
General / Re: LEGO Carcassonne Link
« on: July 15, 2019, 05:43:34 AM »
That's the spirit!!!  :o

5
Official Rules / Re: The wagon and the Big Top.
« on: July 15, 2019, 05:42:36 AM »
IMHO the C1 rules lead to so many restrictions because of the appearance of new (unclaimable) features ending roads through the years (see picture above.) Thus HiG decided, at a certain point, to update the C2 rules and relax those limitations in a way players do not need a detailed list of dos and donts that would be never complete as new expansions are released.

If anyone has some insights on this rules change, please share. We all would be delighted to know more. Thanks.

6
Thank you, Carca_Maker!

It's my pleasure! Happy to help.

See you around with your ideas!  :(y)

7
Good afternoon, Meepledrone!

After reading your before post, I have a doubt... You wrote
"Does 24 / 5040 ring a bell? I think so (See the quadruplas table attached.) Well, it is not rocket science: the probability of drawing any quadrupla is equal to the number of COMBINATIONS  for the quadrupla divided by the total of possible quadruplas."

As far as I know, probability calculations are based on " possible cases divided by the total amount of cases ".
So for 4444 quadrupla, it's 24 combinations and also 24 possible cases... But in another different case of" not coincidence ", for example 1223, your 3221, there are 6 COMBINATIONS at your table, but I think that its probability of extraction is" 72/5040 ", and not" 6/5040 “, Am I right?.
I can see also that the addition of all of quadruplas COMBINATION  data at your table, column, can't do 5040, so I suppose that you really referred to Total [possible] cases of every single  quaterna, etc.  in your table.

Hi there CarcaMaker!

Yes, you are right. I was talking about total combinations (column Total in the previous tables) the intermediate columns are just to keep track of how the final figure is obtained, but for your objectives are irrelevant.

Please find below a new version of the same Excel and PNG files where I hid everything not useful for you. I also renamed the offending column to avoid ambiguities.

I discovered finally a mistake in my "Weights" column, next to your table :
I should be written "x4" at 433 triplet weight. I don't know now if there are more mistakes.

I obtained my "weights" values as the inverse of the (my right calculation?) probability, "possible cases divided by total cases", (this is, its inverse), knowing that the "unitary weight" should be the single Pearl extraction case, this is a "x1", and continuing proportionatelly with the other all cases. Is this right?.

(I wanted to meliorate the rarity of the extractions).
Attentively, waiting your response.

I'm glad you solved the issue.

Eager to hear from you.

Cheers!

8
Hi people! This is a first approximation to my results. It's about trees branches and its weights at my future variant. It's a "dual" file... Sorry. There are pearls 4, emeralds 3, rubíes (in Spanish, red gems, and a diamond!. Thanks Meepledrone, I'm a little busy... I will read your previous post more slowly, I think that I matched with your post, without being read. Luckily!. Cheers!. JEWELS VALIDATIONS AND ITS WEIGHTS.

Hi Carca_Maker,

Take your time. Any other task I can help you with in the meantime?  :)

Cheers!

9
Official Rules / Re: The wagon and the Big Top.
« on: July 13, 2019, 07:22:55 AM »
Hi Windekind!

As per the CII rules, you have several valid destinations for the wagon in the example you mention. There are the three options you point out on the tile framed in red (the tile just placed that causes the wagon to score) plus three other unclaimed, uncompleted roads located on adjacent tiles to the wagon. You even could pick a feature on the same tile as the wagon, if possible. C2 does not require connectivity through roads or common surfaces (for abbeys or monasteries in cities, for example.) 

Just as a reminder, as per the CI rules, the wagon only has one possible valid destination: the road going south. There is no other unoccupied, uncompleted feature connected to the city and, as you indicate, the short roads on the tile at the top are not considered valid for the wagon to move.

Please check the the image below. It marks with blue circles the possible valid destinations for CI rules and CII rules. You can see how CII rules relaxed the requirements exiting in CI rules.

Cheers!

10
General / Re: LEGO Carcassonne Link
« on: July 13, 2019, 01:04:51 AM »
Hi there!

This thread is ages old, but as you can see, people still dream of a Lego and Carcassonne crossover. The idea below is posted on the Lego Ideas site by user ABrickDreamer. You can support it if you like it, of course:

https://ideas.lego.com/projects/116b7d18-d2e8-4d05-af2a-dc5b438767f9

If the idea reaches 10,000 votes, it will be evaluated and considered for an official set. Anyone interested?  ;D
 
A sample image below:



Cheers!

11
Hi Carca_Maker,

I've always seen all probability quizzes related to multiples draws with (or without) replacement been solved by handling one draw at a time. They use probability trees, similar to the trees you use but covering all the cases available. In your trees you are unifying in one case all the possible permutations, that I modeled as symmetries.

Here you can see some examples using probability trees:

http://onemathematicalcat.org/Math/Algebra_II_obj/prob_tree_diagrams.htm

So when you say you draw 4444, you would have a probability tree that assumes that you draw 4 (with probability 4/10) followed by another 4 (with probability 3/9 --> three 4 elements left and 9 elements left in total after the first draw), followed by a third 4 (with probability 2/8) and finally followed by the last 4 (with probability 1 / 7.) So the probability of drawing 4444 is:

P(4444) = ( 4 / 10 ) * ( 3 / 9 ) * ( 2 / 8 ) * ( 1 / 7 ) = 24 / 5040  = 1 / 210

Does 24 / 5040 ring a bell? I think so (See the quadruplas table attached.) Well, it is not rocket science: the probability of drawing any quadrupla is equal to the number of combinations for the quadrupla divided by the total of possible quadruplas. Yeahhhh!

As you can imagine, this also works for pairs and triplets.

Hope this responds to your question.



Appendix: On Symmetries

As a side note, symmetries on the table below are equivalent to the number of possible permutations of quadrupla elements (with repetitions if any of the elements is repeated of course), so:

Let me define k! as the factorial of k, where k! = k * (k -1) * ... * 2 * 1

Therefore:
* The number of permutations of k different elements is equal to k!
* The number of permutations of k when several elements are repeated "a", "b",... "m" times is equal to k! / ( a! * b! * ... * m!)

Thus, If we revisit the value given to some quadruplas cases, we can obtain the number of symmetries as follows:

4321 --> 4! symmetries, no repetition = 24
4331 --> 4! / 2! symmetries, with 1 repetition of two elements = 12
4433 --> 4! / ( 2! * 2! ) symmetries,  with 2 repetitions of two elements each = 6
4441 --> 4! / 3! symmetries, with one repetition of 3 elements = 4
4444 --> 4! / 4! symmetries with one repetition of 4 elements = 1

This is applicable to all the quadruplas according to their particular cases. The objective of this additional exercise was to validate the results for the quadruplas.

Moreover, this can be applied to pairs and triplets. And it is valid for higher dimensions too  >:D

Cheers!

12
If there are any news about the calculations I will let you know.   O0

I'm eager to see how all this impacts your variant. Have fun with the design!

13
Hi, Carca_Maker!

Too beautiful to be fully correct...  :'(

As you requested, some words of wisdom:  :o
1. Never post while watching the finale of Stranger Things Season 3.
2. Never trust the inner calculations are right if the result matches what you expected: there may be errors cancelling each other. In this case:
  - 4 missing quadruplas that added up 600 missing combinations. This is 600 combinations less.
  - An error in the Combinations for quadrupla 4322 and the symmetries for quadruplas 4433 and 3322 that added 600 extra combinations by error.
  - Net sum: 0
3. Contrast your results with an external source: I forgot to do so for the quadruplas as the total number were matching. Thank you for spotting the missing quadruplas and triggering the review.
4. Reasoning in 4D is tricky: Quadruplas such as 4433, 4422 and 3322 present 6 possible symmetries and not 12 as I assumed yesterday because there are 6 possible 4D planes to take into account for the mirroring, and not 12.
5. Reviewing everything after a good sleep is key to find hidden error: And you will do it in a jiffy.

And now, the quadruplas reviewed...

I added the missing quadruples to the listing and marked in pink the offending cells. (Walk of shame for me!)

Cheers!

14
OMG! You are making me blush! It's okay...  :o

It was fun to do all the calculations... A good mathematical challenge from time to time is always welcome.

Now you have to tell us what all this number crunching is good for...

15
General / Re: How to set up a phone alert
« on: July 10, 2019, 03:25:44 PM »
Hi mjwalker,

Can you give more details on the App you are using? It is not my case but people using the same App can maybe shed some light on any configuration settings for example?

Thanks in advance.

Cheers!

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