This section allows you to view all posts made by this member. Note that you can only see posts made in areas you currently have access to.
Messages - Carca_Maker
31
« on: July 11, 2019, 03:08:45 PM »
I forgot a last detail, guys!:
As far as I know,... Is it true that "it's the SAME if I do four (for example) MULTIPLE extractions without replacement one by one?" , than "if I do a SINGLE extraction of four elements in once time?? (From a bag with 10 same balls as I proposed in the starting enunciated), in a probabilistic mode. Greetings.
32
« on: July 11, 2019, 01:17:35 PM »
Ha, ha, ha! Good heavens! The circle seems rounded, and closed. In the beginning it was wrongly "5040", and at last "5040“ rightly ;-). Most probably your calculations now will be right. If you found a mistake, make know it to me, please. " Whatever it be, you are my Tesserackt hero!"Ha, ha, ha! (because those about the four dimensions). You have a place in the acknowlendgements of my variant. Have a good night.
33
« on: July 11, 2019, 10:03:27 AM »
In my variant about "Jewels" there are reserve spaces, best scores, and "doomed Jewels", yeah!.
34
« on: July 11, 2019, 09:54:25 AM »
Ooh! Meepledrone... It looks that there aren't some Quaternas branches, for example your 4221, or 1224, it's the same thing, it's not.
There are an amount of 20 Quaternas branches, remember. Although your computation worths, does the right "5040" cases, so I think that it lacks 4221, 4421, 3221, 4422 branches and their computations.
In the other hand I revised your Triplets computations and they match with mine!.Good job!. I attached here your table for clarification.
I'm using this calculations for to make an expansion in which appears "Jewels" and its combinations. You will see... Thanks. I'm waiting your wisdom words...greetings.
35
« on: July 11, 2019, 06:25:42 AM »
I will, of course!, no doubt.
36
« on: July 11, 2019, 06:23:23 AM »
Ha, ha, ha! The system says that I have to wait one hour for give you another "karma" action, "+1 merit" more.
37
« on: July 11, 2019, 06:19:01 AM »
Congratulations Meepledrone!! I intuited (intuition) that for the triplets, or quadruplas, the lowest quantity of cases were for 333, and 4444, respectively, but there were some hidden, another not obvious "combinations" which amount, worth the same lowest quantity of cases, maybe I saw, I suspected it at my triplets first trying that thanks to you, you "validated" it to me. Although I completed, I wrote that my triplets table one by one, I weren't sure at all. I'm going to compare my first trying of triplets table with yours, I suppose they match... Since I sent you my pairs table, etc, you understood that, great!. I only can say that I lift my hat!. You beated the "final big boss monster" of my maths mess!. I give you +2 merits. Now I will apply it to my variant... Thanks Meepledrone!.
38
« on: July 10, 2019, 08:35:17 AM »
It's important to say that the my triplets notation at the previous picture, means that, for example "432“ means every triplet containing that three elements. Because of it, the total amount of triplets is 720 cases, and no the other smaller result of Meepledrone's supose #2.
39
« on: July 10, 2019, 02:58:04 AM »
Good morning! As Meepledrone said at his "Case #1: Elements in different order represent different sets" the triplets, 720 cases match with my old solution, here you are a picture.
So, it's only needed by me the solution and solving for Quaternas branches, at the beginning, supposing "Case #1: Elements in different order represent different sets". Ok and thanks.
40
« on: July 09, 2019, 03:26:22 PM »
And written in the right way, I add : "Case #1: Elements in different order represent different sets", in the Meepledrone terms.
41
« on: July 09, 2019, 03:12:47 PM »
Good evening, Meepledrone! First of all, I wish to give you a "+1" merit, no doubt, you are a math sage!. Afterwards I will have to read better what you wrote, but in a first approximation I think that "90" cases for pairs, "720" for triplets , etc is the right way.
42
« on: July 09, 2019, 02:59:23 PM »
Hola DrMeeple! Efectivamente, es el que me señala el sabio de Meepledrone. Son las ramas de los árboles de mis ternas y cuaternas respecto de mis 10 elementos. Y qué reto querías compartir por aquí Carca Marker?? emoji code4]
Enviado desde mi XT1700 mediante Tapatalk
Enviado desde mi H3311 mediante Tapatalk
43
« on: July 09, 2019, 10:46:31 AM »
Hello Meepledrone! I'm not still familiarized with "quote" action, though my smartphone, it's difficult seeing from it. Sorry. I'm going to talk from "recently" memory.
That's a good idea to identify the four kinds of elements with A, B, C, D.
I can say that your two calculations, look like, seem to "unify" some cases belonging to a "upper", category of cases. "120“ cases, and "210“ approximately in the other hand, it seems to me a nice approximation to the goal, because it's not a huge amount of rather cases. But I don't still know what does it means, so brief numbers.
Now, the question is how to FIT your first calculation, to the most simple cases, that I know and I calculated too: the PAIRS of elements. (And the trivial singles cases too in one table).
I would be glad if your mathematical model can get to, describe the same as my table of pairs. This is, how many cells are belonging to each pair, etc?. That's the question that I need for first approximation, for every trees and its branches.
Posdata: The cells of this pairs table are empty, because are an example.Thanks.
44
« on: July 08, 2019, 02:31:38 PM »
Meepledrone, I sized both two images when I uploaded them, to a A4 printable size. I don't know if that is the matter of the trouble. I'm going to souper, it's late, and disconnect. Bye.
45
« on: July 08, 2019, 02:11:37 PM »
Sorry... Maybe the two images that I accompanied are too big for a smartphone screen? Tell me if it does. Carca_Maker.
|